y=3x2−2x3y = 3x^{2} - 2x^{3}y=3x2−2x3
dydx=6x−6x2=0 ⟹ 6x(1−x)=0\frac{dy}{dx} = 6x - 6x^{2} = 0 \implies 6x(1 - x) = 0dxdy=6x−6x2=0⟹6x(1−x)=0
x=0,1x = 0, 1x=0,1, when x = 1, y = 0.
when x = 1, y = 0.
The stationary point is (1, 0)
