Solve; P/2 + k/3 = 5 and 2p = k = 6 simultaneously

Correct Answer is : p = 6, k = 6

Correct Answer is : p = 6, k = 6

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WAEC Further Mathematics 2019 Paper

Question : 2

Total: 39

Solve;

\frac{P}{2} + \frac{k}{3}

= 5 and 2p = k = 6 simultaneously

Solution:

$\frac{P}{2} + \frac{k}{3}$ = 5

$\frac{3p + 2k}{6}$ = 5

2p + 3k = 30

- 2p - k = 6

$\overline{\frac{4k}{4} = \frac{24}{4}}$

k = 6

From 2p - k = 6

2p - 6 = 6

$\frac{2p}{2} = \frac{12}{2}$

p = 6

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