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WAEC Further Mathematics 2020 Paper

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Question : 4

Total: 39

If

\int\limits_{0}^{3}(px^2 + 16)dx

= 129. Find the value of p.

9
8
7
6

Solution:

Concept:

Use definite integration to form an equation in

p

.

Explanation:

Integrate the given function from

0

to

3

:

\int_0^3 (px^2 + 16)\,dx = \left[\frac{px^3}{3} + 16x\right]_0^3

Evaluate at the upper and lower limits:

\left(\frac{p(3)^3}{3} + 16(3)\right) - 0 = 129

This simplifies to:

9p + 48 = 129

Subtract

48

from both sides:

9p = 81

Divide by

9

:

p = 9

Answer:

p = 9

Option A.

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