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WAEC Further Mathematics 2020 Paper

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Question : 8

Total: 39

If

\frac{6x\;+\;k}{2x^{2}\;+\;7x\;-\;15}

\frac{4}{x\;+\;5} - \frac{2}{2x\;-\;3}

. Find the value of k.

- 21
- 22
- 24
- 25

Solution:

$\frac{6x\;+\;k}{2x^{2}\;+\;7x\;-\;15} = \frac{4}{x\;+\;5} - \frac{2}{2x\;-\;3}$

6x + k = 4 (2x - 3) - 2(x + 5)

6x + k = 8x - 12 - 2x - 10

6x + k = 6x - 22

k = - 22

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