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WAEC Further Mathematics 2021 Paper

Question : 34

Total: 38

^2

^2

- 6y -2 = 0.

Solution:

2x $^3$ - 4x + 2y $^2$ - 6y - 2 = 0

Divide through by 2: x $^2$ - 2x + y $^2$ -3y -1 = 0

x $^2$ -2x + y $^2$ - 3y = 1

x $^2$ -2x + 1 + y $^2$ - 3y + 9/4

= 1+ 1 + 9/4

= (x- 1) $^2$ (y - 3/2) $^2$

= √[17/4]

r = √17/2

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