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WAEC Further Mathematics 2021 Paper

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Question : 5

Total: 38

Solve (

\frac{1}{9}

^{x+2}

^{x-2}

$\frac{7}{5}$
$\frac{6}{7}$
$\frac{-7}{6}$
$\frac{-6}{7}$

Solution:

( $\frac{1}{9}$ ) $^{x+2}$ = 243 $^{x-2}$

3 $^{-2(x+2)}$ = 3 $^{5(x-2)}$ ;

-2(x+2) = 5(x - 2)

-2x -4 = 5x - 10

-7x = -6

x = $\frac{6}{7}$

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