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WAEC Further Mathematics 2021 Paper

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Question : 9

Total: 38

If α and β are the roots of 3x

^2

- 7x + 6 = 0, find

\;\frac{1}{\alpha}

\;\frac{1}{\beta}

$\;\frac{7}{6}$
$\;\frac{7}{3}$
$\;\frac{14}{5}$
$\;\frac{14}{3}$

Solution:

3x $^2$ - 7x + 6 = 0

α + β = $\;\frac{7}{3}$ ;

αβ = 2;

$\;\frac{1}{\alpha}$ + $\;\frac{1}{\beta}$ = $\;\frac{\alpha\;+\beta}{\alpha\beta}$

$\;\frac{7}{3}$ ÷ 2

= $\;\frac{7}{6}$

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