32x−2−28(3x−2)+3=03^{2x-2} - 28(3^{x-2}) + 3 = 032x−2−28(3x−2)+3=0
32x32−28.3x32+3=0\frac{3^{2x}}{3^2} - \frac{28.3^x}{3^2} + 3 = 03232x−3228.3x+3=0
32x9−28.3x9+3=0\frac{3^{2x}}{9} - \frac{28.3^x}{9} + 3 = 0932x−928.3x+3=0
let p = 3x^{x}x
p29−28p9+3=0\frac{p^{2}}{9} - \frac{28p}{9} + 3 = 09p2−928p+3=0
multiply through by 9