If g(x) = √(1-x²), find the domain of g(x)

Correct Answer is : -1 ≤ x ≤ 1

Correct Answer is : -1 ≤ x ≤ 1

Test Index

WAEC Further Mathematics 2022 Paper

Question : 29

Total: 45

^2

), find the domain of g(x)

Solution:

Concept:

For a square root function, the expression inside the root must be non-negative.

Explanation:

Given

g(x) = \sqrt{1-x^2}

, the radicand must satisfy:

1 - x^2 \ge 0

Rearrange the inequality:

x^2 \le 1

Take the square root of both sides:

|x| \le 1

This means

x

lies between

-1

and

1

, inclusive:

-1 \le x \le 1

Answer:

Option C:

-1 \le x \le 1

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