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WAEC Further Mathematics 2022 Paper

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Question : 3

Total: 45

If

\log_{10}(3x-1) + \log_{10}4 = \log_{10}(9x+2)

, find the value of x

$\; \frac{1}{3}$
1
2
3

Solution:

$\log_{10}(3x - 1) + \log_{10}4 = \log_{10}(9x+2)$

$\log_{10}4(3x-1) = \log_{10}(9x+2)$

4(3x - 1) = 9x + 2

12x - 4 = 9x + 2

12x - 9x = 2 + 4

3x = 6

x = 2

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