(19)2x−1=(181)2−3x\left(\frac{1}{9}\right)^{2x-1} = \left(\frac{1}{81}\right)^{2-3x}(91)2x−1=(811)2−3x
(19)2x−1=(19)2(2−3x)\left(\frac{1}{9}\right)^{2x-1} = \left(\frac{1}{9}\right)^{2(2-3x)}(91)2x−1=(91)2(2−3x)
(19)2x−1=(19)4−6x\left(\frac{1}{9}\right)^{2x-1} = \left(\frac{1}{9}\right)^{4-6x}(91)2x−1=(91)4−6x
Since the bases are equal, powers can be equated
= 2x - 1 = 4 - 6x
= 2x + 6x = 4 + 1
= 8x = 5
∴x=58\therefore x = \frac{5}{8}∴x=85
