22x - 5(2x) + 4 = 0
2(x)2 - 5(2x) + 4 = 0
let p = 2x
p2 - 5(p) + 4 = 0
p2 -4p - p + 4 = 0
p(p - 4) - 1(p - 4) = 0
(p - 1)(p -4) = 0
p = 1 or 4
But p = 2x = 1 or 4
2x = 22
x = 2
2x = 20 = 1
x = 0
Therefore, the values of x = 0 and 2