If y² + 2xy - 8 = 0, find \;dy/dx

Correct Answer is : −yy+x\;-y/y+xy+x−y

Correct Answer is : −yy+x\;-y/y+xy+x−y

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WAEC Further Mathematics 2024 Paper

Question : 31

Total: 40

If y

^{2}

\;\frac{dy}{dx}

Solution:

y $^{2}$ + 2xy - 8 = 0

$\;\frac{dy}{dx}$ = 2y $\;\frac{dy}{dx}$ + 2y + 2x $\;\frac{dy}{dx}$ = 0

= 2y $\;\frac{dy}{dx}$ + 2x $\;\frac{dy}{dx}$ = -2y

$\;\frac{dy}{dx}$ = $\;\frac{-2y}{2(y+x)}$ = $\;\frac{-y}{y+x}$

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