Test Index

WAEC Further Mathematics 2024 Paper

Question : 8

Total: 40

If log

{}_{2}^{x}

{}_{x}^{128}

Solution:

log ${}_{2}^{x}$ = 2, in index form = x = 2 ${}^{2}$ = 4

So, log ${}_{x}^{128}$ = log ${}_{4}^{128}$ = log ${}_{2^{2}}^{2^{7}}$ = $\;\frac{7}{2}$ log ${}_{2}^{2}$ = $\;\frac{7}{2}$

Go to Question:

Prev Question

Next Question