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WAEC Mathematics 2010 Paper
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© africaexams.com
Question : 16
Total: 49
If sin 3y = cos 2y and 0
o
≤
90
o
, find the value of y
18
o
36
o
54
o
90
o
Validate
Solution:
sin 3y = cos 2y, but sin
θ
= cos(90 -
θ
)
sin 3y = cos(90 - 3y)
cos(90 - 3y) = cos 2y
90 - 3y = 2y
5y = 90
y =
90
5
y = 18
o
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