mean age = no. of mensum of ages50=R∑ sum = 50R.....(1) Sum of ages of the men that left = 55 + 63 = 188 remaining sum = 50R - 118 remaining no. of men = R - 2 now mean age = 50 - 1 = 49 years 49 = R−250R−118 49(R - 2) = 50R - 118 49R - 50R = -188 - 98 -R = -20 R = 20