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WAEC Mathematics 2010 Paper

Question : 8

Total: 49

\leq x \leq 6

\leq x \leq 10

\cap

Solution:

Concept:

Find the common elements in the two integer sets and count them.

Explanation:

Write each set by listing all integers in the given range.

P = \{1, 2, 3, 4, 5, 6\}

Q = \{2, 3, 4, 5, 6, 7, 8, 9, 10\}

The intersection

P \cap Q

contains only elements present in both sets.

P \cap Q = \{2, 3, 4, 5, 6\}

Count the elements: there are 5 elements.

So,

n(P \cap Q) = 5

Answer:

A. 5

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