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WAEC Mathematics 2011 Paper

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Question : 5

Total: 47

If a number is chosen at random from the set {x: 4

\leq x \leq 15

}. Find the probability that it is a multiple of 3 or a multiple of 4

$\;\frac{1}{12}$
$\;\frac{5}{12}$
$\;\frac{7}{12}$
$\;\frac{11}{12}$

Solution:

set = 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

multiple of 3 = 6, 9, 12, 15

multiple of 4 = 4, 8, 12

Prob(multiple of 3 or 4) = Prob(multiple of 3) + pro(multiple of 4)

=

\;\frac{4}{12} + \;\frac{3}{12} = \;\frac{7}{12}

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