WAEC Mathematics 2012 Paper

L + 30^o - 180^o(Sum of < s on straight line)L = 180^o - 30^o = 150^oL = q = 150^o(opposite < s are equal)y = b = 30^o(alt. < s)b + c = 180^o(sum of < s on str. line)30^o + c 180c = 180 - 30 c = 150^o b = a = 30^o (opp < s are equal) c = d = 150^o (opp < s are equal)a + k + 70^o = 180^o (sum of < s on $\triangle$)30^o + k + 70^o = 180k + 100^o = 180k = 180 - 100k = 80^o x + 80^o = 180(sum of < s on straight line) x = 180^o - 80^o x = 100^o