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WAEC Mathematics 2013 Paper

Question : 13

Total: 48

Given that

p^{\frac{1}{3}}

\frac{\sqrt[3]{q}}{r}

, make q the subject of the equation

Solution:

$p^{\frac{1}{3}}$ = $\frac{\sqrt[3]{q}}{r}$

cross multiply

p^{\frac{1}{3}}

\frac{q^{\frac{1}{3}}}{r}

r $p^{\frac{1}{3}}$ = $q^{\frac{1}{3}}$

take the cube of both sides

$\left(r p^{\frac{1}{3}}\right)^3$ = $\left(q^{\frac{1}{3}}\right)^3$

$r^3 p^{\frac{3}{3}}$ = $q^{\frac{3}{3}}$

$r^3$ p = q

∴ q = p $\sqrt{r}$

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