Test Index

WAEC Mathematics 2015 Paper

Question : 26

Total: 45

\frac{2}{3}

\frac{3}{4}

\frac{4}{5}

Solution:

Concept:

Only Kebba hits the target means Kebba succeeds while both Ebou and Omar miss.

So, multiply the probability of Kebba hitting by the complementary probabilities of Ebou and Omar missing.

Explanation:

Given:

P(K) = \frac{2}{3}

P(E) = \frac{3}{4}

P(O) = \frac{4}{5}

Probability that Ebou misses:

P(E') = 1 - \frac{3}{4} = \frac{1}{4}

Probability that Omar misses:

P(O') = 1 - \frac{4}{5} = \frac{1}{5}

Required probability:

P(\text{only Kebba hits}) = P(K) \times P(E') \times P(O')

= \frac{2}{3} \times \frac{1}{4} \times \frac{1}{5}

= \frac{2}{60}

= \frac{1}{30}

Answer:

\frac{1}{30}

Correct option: C.

Go to Question:

Prev Question

Next Question