Test Index

WAEC Mathematics 2015 Paper

© africaexams.com

Question : 35

Total: 45

A farmer uses

\frac{2}{5}

of his land to grow cassava,

\frac{1}{3}

of the remaining for yam and the rest for maize. Find the part of the land used for maize

$\frac{2}{15}$
$\frac{2}{5}$
$\frac{2}{3}$
$\frac{4}{5}$

Solution:

Let x represent the entire farmland

then,

\frac{2}{5}

x +

\frac{1}{3}

[x -

\frac{2}{3}x

] + M = x

Where M represents the part of the farmland used for growing maize, continuing

\frac{2}{5}

x +

\frac{1}{3}

x [1 -

\frac{2}{3}x

] + M = x

\frac{2}{5}x + \frac{1}{3}

x [

\frac{3}{5}

] + M = x

\frac{2}{5}

x +

\frac{1x}{5}

+ M = x

\frac{3x}{5} + M = x

M = x -

\frac{2}{5}

x

= x[1 -

\frac{3}{5}

]

= x[

\frac{2}{5}

] =

\frac{2x}{5}

Hence the part of the land used for growing maize is

\frac{2}{5}

© africaexams.com

Go to Question:

Prev Question

Next Question