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WAEC Mathematics 2015 Paper

Question : 40

Total: 45

Calculate the mean deviation of 5, 3, 0, 7, 2, 1

Solution:

Concept:

Mean deviation is the average of the absolute differences between each data value and the mean of the data set.

Explanation:

First, calculate the arithmetic mean.

\overline{x} = \frac{5 + 3 + 0 + 7 + 2 + 1}{6}

\overline{x} = \frac{18}{6} = 3

Now find the absolute deviation of each value from the mean,

|x - \overline{x}|

|5 - 3| = 2

|3 - 3| = 0

|0 - 3| = 3

|7 - 3| = 4

|2 - 3| = 1

|1 - 3| = 2

Add all the absolute deviations.

2 + 0 + 3 + 4 + 1 + 2 = 12

Apply the mean deviation formula.

MD = \frac{\sum |x - \overline{x}|}{n}

MD = \frac{12}{6} = 2

Answer:

Mean deviation is

2.0

Correct option: B.

2.0

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