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WAEC Mathematics 2017 Paper

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Question : 46

Total: 49

The diagonal of a square is 60 cm. Calculate its peremeter

20 $\sqrt{2}$
40 $\sqrt{2}$
90 $\sqrt{2}$
120 $\sqrt{2}$

Solution:

$60^2 + x^2 + x^2$

$360^2 = 2x^2$

$x^2$ = 1800

x = $\sqrt{1800}$

x = 42.4264

x = 42.4264

perimeter = 4x

= 4 x 42.4264

= 169.7056

= 120 $\sqrt{2}$

= 120 $\sqrt{2}$

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