WAEC Mathematics 2018 Paper

In the diagram, < WOZ = 180$^{\circ}$ (angle on a straight line)

< WOX = < XOY = < YOZ

(|WX| = |XY| = |YZ|)

$\; \frac{180^{\circ}}{3}$ = 60$^{\circ}$

= 60$^{\circ}$

M + m =2m (base angles of isosceles $\triangle$, |OY| and |OZ| are radii)

< YOZ + 2m (base angles of a $\triangle$)

60$^{\circ}$ + 2m = 180$^{\circ}$ (sum of a $\triangle$)

60$^{\circ}$ + 2m = 180$^{\circ}$

2m = 180$^{\circ}$ - 60$^{\circ}$

2m = 120$^{\circ}$

m = $\; \frac{120^{\circ}}{2}$

= 60$^{\circ}$