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WAEC Mathematics 2018 Paper

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Question : 47

Total: 50

Given that Y is 20cm on a bearing of 300

^{\circ}

from x, how far south of y is x?

10cm
15cm
25cm
30cm

Solution:

In $\triangle$ YSC, sin 30 $^{\circ}$ = $\; \frac{YS}{20}$

|YS| = 20 sin 30 $^{\circ}$

= 20 x 0.5

10m

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