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WAEC Mathematics 2019 Paper

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Question : 12

Total: 50

H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y.

H = $\;\frac{p}{4y^2}$
H = $\;\frac{2p}{y^2}$
H = $\;\frac{p}{2y^2}$
H = $\;\frac{p}{y^2}$

Solution:

H $∝$ $\;\frac{p}{y^2}$

H = $\;\frac{pk}{y^2}$

1 = $\;\frac{8k}{2^{2}}$

k = $\;\frac{4}{8}$

= $\;\frac{1}{2}$

H = $\;\frac{p}{2y^2}$

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