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WAEC Mathematics 2019 Paper

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Question : 22

Total: 50

If 2

{}^a

\sqrt{64}

\; \frac{b}{a}

= 3, evaluate a

{}^2 + b^{2}

250
160
90
48

Solution:

2 ${}^a$ = $\sqrt{64}$

2 ${}^a$ = 8

2 ${}^a$ = 2 ${}^3$

a = 3

b = 3 ${}^a$

b = 3 x 3 = 9

a ${}^2$ + b ${}^2$ = 3 ${}^2$ + 9 ${}^2$

= 9 + 81 = 90

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