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WAEC Mathematics 2019 Paper

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Question : 30

Total: 50

In the diagram, POS and ROT are straight lines. OPQR is a parallelogram, |OS| = |OT| and ∠OST = 50°. Calculate the value of ∠OPQ.

100 $^{\circ}$
120 $^{\circ}$
140 $^{\circ}$
160 $^{\circ}$

Solution:

S $O$ T = 180 $^{\circ}$ - (50 + 50)

= 80 $^{\circ}$

P $Q$ R = 80 $^{\circ}$

= $\frac{360^{\circ} - 160^{\circ}}{2}$ = 100 $^{\circ}$

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