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WAEC Mathematics 2019 Paper

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Question : 32

Total: 50

The interior angles of a polygon are 3x

^{\circ}

^{\circ}

^{\circ}

^{\circ}

^{\circ}

. Find the size of the smallest angle of the polygon.

80 $^{\circ}$
60 $^{\circ}$
40 $^{\circ}$
30 $^{\circ}$

Solution:

3 $x^{\circ}$ + 2 $x^{\circ}$ + 4 $x^{\circ}$ + 3 $x^{\circ}$ + 6 $x^{\circ}$ = 540 $^{\circ}$

$\; \frac{18x^{\circ}}{18} = \; \frac{540^{\circ}}{18}$

$x^{\circ}$ = 30 $^{\circ}$

Smallest angle = 2 x 30 $^{\circ}$ = 60 $^{\circ}$

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