Test Index

WAEC Mathematics 2019 Paper

© africaexams.com

Question : 36

Total: 50

If tan x =

\;\frac{3}{4}

^{\circ}

\;\frac{\cos\;x}{2\;\sin\;x}

$\;\frac{8}{3}$
$\;\frac{3}{2}$
$\;\frac{4}{3}$
$\;\frac{2}{3}$

Solution:

y $^2$ = 3 $^2$ + 4 $^2$

y $^2$ = 9 + 16

y = $\sqrt{25}$

= 5

$\;\frac{\cos\;x}{2\;\sin\;x} = \;\frac{4}{5} + 2 \times \;\frac{3}{5}$

= $\;\frac{4}{5} \times \;\frac{5}{6}$

= $\;\frac{2}{3}$

© africaexams.com

Go to Question:

Prev Question

Next Question