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WAEC Mathematics 2019 Paper

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Question : 44

Total: 50

In the diagram, PQ is parallel to RS, < QFG = 105

^o

^o

. Find the value of n

40 $^o$
55 $^o$
75 $^o$
130 $^o$

Solution:

E $G$ R = 50 $^o$ (Alternative angles)

n + 55 $^o$ + 50 $^o$ = 180 $^o$ (Sum of angles on a straight line)

n = 180 $^o$ - 105 $^o$

n = 75 $^o$

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