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WAEC Mathematics 2019 Paper

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Question : 50

Total: 50

Evaluate:

\;\frac{0.42 \div 2.5}{0.5 \times 2.95}

, leaving the answer in the standard form.

1.639 x 10 $^2$
1.639 x 10 $^1$
1.639 x 10 $^{-1}$
1.639 x 10 $^{-2}$

Solution:

$\;\frac{0.42 \div 2.5}{0.5 \times 2.05} = \;\frac{0.168}{1.025}$

= 1.639 x 10 $^{-1}$

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