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WAEC Mathematics 2019 Paper

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Question : 8

Total: 50

If 23

_y

_{\;\text{two}\;}

, find the value of y

4
5
6
7

Solution:

23 $_y$ = 1111 $_{\;\text{two}\;}$ ,

2 x y $^1$ + 3 x y $^0$ = 1 x 2 $^3$ + 1 x 2 $^1$ + 1 x 2 $^{\circ}$

2y + 3 = 8 + 4 + 2 + 1

2y + 3 = 15

$\;\frac{2y}{2}$

$\;\frac{12}{2}$

y = 6

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