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WAEC Mathematics 2020 Paper

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Question : 36

Total: 48

A box contains 12 identical balls of which 5 are red, 4 blue, and the rest are green. If a ball is selected at random from the box, what is the probability that it is green?

$\,\frac{3}{4}$
$\,\frac{1}{2}$
$\,\frac{1}{3}$
$\,\frac{1}{4}$

Solution:

No. of red = 5

No. of blue = 4

No. of green = 3

Total = 12

Pr(Green) = $\,\frac{3}{12} = \,\frac{1}{4}$

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