2x−3\frac{2}{x-3}x−32 - 3x−2\frac{3}{x-2}x−23
= 2(x−2)−3(x−3)(x−3)(x−2)\frac{2(x-2)-3(x-3)}{(x-3)(x-2)}(x−3)(x−2)2(x−2)−3(x−3)
= 2x−4−3x+9(x−3)(x−2)\frac{2x-4-3x+9}{(x-3)(x-2)}(x−3)(x−2)2x−4−3x+9
= 5−x(x−3)(x−2)\frac{5-x}{(x-3)(x-2)}(x−3)(x−2)5−x
