Concept:When a fair die is tossed twice, each toss has 6 outcomes, so the total sample space is 6×6=36.Explanation:We need outcomes whose sum is at least 10.Favorable outcomes are: (4,6),(5,5),(6,4),(5,6),(6,5),(6,6).Thus, number of favorable outcomes, n(E)=6.Total possible outcomes, n(S)=36.Required probability =n(S)n(E)=366=61.Answer:61, which corresponds to option D.