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WAEC Mathematics 2021 Paper

Question : 8

Total: 49

\frac{1}{6}

\frac{7}{12}

\frac{1}{4}

Solution:

Concept:

We need to find the unknown number by subtracting it from the total sum to match the given result.

Explanation:

Step 1: Write the mixed numbers as improper fractions.

2\frac{1}{6} = \frac{13}{6}

2\frac{7}{12} = \frac{31}{12}

3\frac{1}{4} = \frac{13}{4}

Step 2: Find the sum of the first two fractions.

\frac{13}{6} + \frac{31}{12} = \frac{26}{12} + \frac{31}{12} = \frac{57}{12}

Step 3: Let the required number be

y

\frac{57}{12} - y = \frac{13}{4}

So,

y = \frac{57}{12} - \frac{13}{4}

Step 4: Convert

\frac{13}{4}

to twelfths.

\frac{13}{4} = \frac{39}{12}

Therefore,

y = \frac{57}{12} - \frac{39}{12} = \frac{18}{12} = \frac{3}{2} = 1\frac{1}{2}

Answer:

1\frac{1}{2}

(Option B)

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