WAEC Mathematics 2021 Paper

The sum of 2 $\frac{1}{6}$ and 2$\frac{7}{12}$

= $\frac{13}{6}$ + $\frac{31}{12}$

= $\frac{13 \times 2 + 31}{12}$

= $\frac{26 + 31}{12}$

= $\frac{57}{12}$

What should be subtracted from $\frac{57}{12}$ to give 3$\frac{1}{4}$

$\frac{57}{12}$ - y = 3$\frac{1}{4}$

: y = $\frac{57}{12}$ - 3$\frac{1}{4}$ = $\frac{57}{12}$ - $\frac{13}{4}$

y = $\frac{57 - 3 \times 13}{12}$ = $\frac{57 - 39}{12}$

y = $\frac{18}{12}$

y = $\frac{3}{2}$ or 1$\frac{1}{2}$