.Find the value of x such that 1/x +4/3x - 5/6x + 1 = 0

Correct Answer is : −32-3/22−3

Correct Answer is : −32-3/22−3

Test Index

WAEC Mathematics 2022 Paper

Question : 17

Total: 47

\frac{1}{x}

\frac{4}{3x}

\frac{5}{6x}

+ 1 = 0

Solution:

$\frac{1}{x}$ + $\frac{4}{3x}$ - $\frac{5}{6x}$ + 1 = 0

using 6x as lcm

→ $\frac{6+8-5+6x}{6x}$

→ $\frac{9+6x}{6x}$ = 0

9+6x = 0

6x = -9

x = $\frac{-9}{6}$ or $\frac{-3}{2}$

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