.Find the value of x such that 1/x +4/3x - 5/6x + 1 = 0

Correct Answer is : −32-3/22−3

Correct Answer is : −32-3/22−3

Test Index

WAEC Mathematics 2022 Paper

Question : 17

Total: 47

\frac{1}{x}

\frac{4}{3x}

\frac{5}{6x}

+ 1 = 0

Solution:

Concept:

Combine the algebraic fractions using a common denominator, then solve the resulting linear equation.

Explanation:

Take the LCM of the denominators as

6x

\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1 = \frac{6+8-5+6x}{6x}

Simplify the numerator:

6+8-5+6x = 9+6x

Thus,

\frac{9+6x}{6x} = 0

A fraction equals zero only when its numerator is zero.

9+6x = 0

6x = -9

x = \frac{-9}{6} = \frac{-3}{2}

This matches option C.

Answer:

x = \frac{-3}{2}

(Option C)

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