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WAEC Mathematics 2022 Paper

Question : 2

Total: 47

Change 432

_{five}

to a number in base three.

Solution:

Convert from base 5 to base 10

432 $_{five}$ = (4 x 5 $^2$ ) + (3 x 5 $^1$ ) + (2 x 5 $^0$ )

= (4 x 25) + (3 x 5) + (2 x 1)

= 100 + 15 + 2

= 117 $_{ten}$

Then convert from base 10 to base 3

Selecting the remainders from bottom to top:

117 $_{ten}$ = 11100 $_{three}$

Hence; 432 $_{five}$ = 11100 $_{three}$

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