Since the mean of the two numbers x and y is:
x+y2\frac{x+y}{2}2x+y = 4
x+y =2 * 4
x+y = 8
then we get:
x+2x+y+2y4\frac{x+2x+y+2y}{4}4x+2x+y+2y
=(3x+3y4\frac{3x+3y}{4}43x+3y)
= 3(x+y4\frac{x+y}{4}4x+y) → 3(84\frac{8}{4}48)
= 3 * 2
= 6
