WAEC Mathematics 2023 Paper

%error=5%, measured height = 5.98m

let the actual height = y

error=x - 5.98 (since 'y' is more than 5.98)

%error = $\; \frac{\text{error}}{\text{actual height}} \times 100\%$

5% = $\; \frac{y-5.98}{y} \times 100\%$

$\; \frac{5}{100} = \; \frac{y-5.98}{y}$

5y = 100(y - 5.98)

5y = 100y - 598

5y - 100y = - 598

-95y = - 598

y = $\; \frac{-598}{-95}$

y = 6.29m( to 2 d.p).