make x the subject of the relation y = ax³ - b/3z

Correct Answer is : x = 3yz+ba3[3]{3yz + b/a}3a3yz+b

Correct Answer is : x = 3yz+ba3[3]{3yz + b/a}3a3yz+b

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WAEC Mathematics 2023 Paper

Question : 22

Total: 50

y = \frac{ax^3 - b}{3z}

Solution:

$y = \frac{ax^3 - b}{3z}$

cross multiply

$ax^3 - b$ = 3yz

$ax^3$ = 3yz + b

divide both sides by a

$x^3 = \frac{3yz + b}{a}$

take cube root of both sides

therefore, x = $\sqrt[3]{\frac{3yz + b}{a}}$

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