Tanθ=oppadj\theta = \frac{opp}{adj}θ=adjopp
Tanθ=56110\theta = \frac{56}{110}θ=11056
θ=tan1(0.5091)\theta = \tan^1(0.5091)θ=tan1(0.5091)
therefore, θ\thetaθ = 27° ( to the nearest degree)