WAEC Mathematics 2023 Paper

Let A = (1, -3), B = (6, 2) and C = (0,4)

d=√(y2−y1)2+(x2−x1)2
|AB| = √(2−(−3))2+(6−1)2
= √(2+3)2+(6−1)2
= √52+52
= √25+25
= √50
= 5√2 units

|BC| = √(4−2)2+(0−6)2
= √22+(−6)2
= √4+36
= 4√0
= 2√10 units

|AC| = √(4−(−3)2+(0−1)2
= √(4+3)2+(0−1)2
= √72+(−1)2
= √49+1
= √50
= 5√2 units

Since two sides are equal (|AB| = |AC|), then the triangle is Isosceles.