2x - 3y = -11 --- (i)3x + 2y = 3 --- (ii)Multiply equation (i) by 3 and equation (ii) by 26x - 9y = -33 --- (iii)6x + 4y = 6 --- (iv)Subtract equation (iii) from (iv)13y = 39
y = 3913 = 3
substitute (3) for y in equation (ii)3x + 2(3) = 33x + 6 = 33x = 3 - 63x = -3x = −33 = - 1
Now,(y−x)2=(3−(−1))2= (3+1)2= 42= 16