M∝n2qM \propto n^2\sqrt{q}M∝n2q
M=Kn2qM = K n^2\sqrt{q}M=Kn2q
K = Mn2q\;\frac{M}{n^2\sqrt{q}}n2qM
K = 24224\;\frac{24}{2^2\sqrt[4]{}}22424
k = 248=3\;\frac{24}{8}=3824=3
Now, let's find M when n = 5 and q = 9
M = Kn2qK n^2\sqrt{q}Kn2q
M = 3×5293 \times 5^2 \sqrt{9}3×529
M=3×25×3M = 3 \times 25 \times 3M=3×25×3
Therefore, M = 225.