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WAEC Mathematics 2024 Paper

Question : 14

Total: 50

\; \frac{22}{7}

)

Solution:

The total surface area A of a closed cylindrical barrel (closed at one end), is given by:

A = πr

^2

+ 2πrh = πr(r + 2h)

BUT, r = 0.245m, h = 2.5m

A = $\; \frac{22}{7}$ x 0.245( 0.245 + 2 x 2.5)

A = 0.77(5.245) = 4.038650m $^2$ ≈ 4.0m $^2$

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