In the diagram above, O is the centre of the circle. If | OA‾\overline{OA}OA = 25 cm and |AB‾\overline{AB}AB = 40 cm, find |OH‾\overline{OH}OH|
Line OH divides Line AB into two halves, therefore, Line AH = Line HB = 20cm
Considering △\triangle△ AOH
(OH‾)2\overline{OH})^2OH)2 = 252^22 - 202^22 = 625 - 400 = 225
Taking the square root of both sides
(OH‾\overline{OH}OH = 225\sqrt{225}225 = 15 cm