In the diagram above, PQ‾\overline{PQ}PQ || RS‾\overline{RS}RS, ∠\angle∠WYZ = 44º and ∠\angle∠WXY = 50º. Find ∠\angle∠WTX
∠\angle∠XWY = ∠\angle∠ZYW = 44º (alternate ∠\angle∠s)
Considering △\triangle△WTX
∠\angle∠W + ∠\angle∠T + ∠\angle∠X = 180º
44 + ∠\angle∠T + 50 = 180
∠\angle∠T = 180 - 44 - 50 = 86º
